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3g of activated charcoal was added to 50...

`3g` of activated charcoal was added to 50mL of acetic acid solution `(0.06N)` in a flask. After an hour it was filtered and the strength of the filtrate was found to be `0.042N` . The amount of acetic adsorbed (per gram of charcoal) is:

A

18 mg

B

36 mg

C

42 mg

D

54 mg

Text Solution

Verified by Experts

Let the weight of acetic acid initially be `W_1` in 50 ml of 0.06N
`O=V100/6050`
After one hour, the strength of acetic acid=0.042 N
`O=V100/6450`
So the amount of acetic acid adsorbed per 3g = 180 – 126 = 54 mg
Amount of acetic acid adsorbed per `g=18^(54)/3 mg`
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