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If vec(A) and vec(B) are perpendicular V...

If `vec(A)` and `vec(B)` are perpendicular Vectors and vector `vec(A)= 5hat(i)+7hat(j)-3hat(k)` and `vec(B)= 2hat(i)+2hat(j)-ahat(k)`. The value of `a` is

A

`-2`

B

8

C

`-7`

D

`-8`

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The correct Answer is:
To find the value of \( a \) such that the vectors \( \vec{A} \) and \( \vec{B} \) are perpendicular, we will follow these steps: ### Step 1: Write down the vectors We have: \[ \vec{A} = 5\hat{i} + 7\hat{j} - 3\hat{k} \] \[ \vec{B} = 2\hat{i} + 2\hat{j} - a\hat{k} \] ### Step 2: Use the condition for perpendicular vectors Two vectors are perpendicular if their dot product is zero: \[ \vec{A} \cdot \vec{B} = 0 \] ### Step 3: Calculate the dot product The dot product \( \vec{A} \cdot \vec{B} \) is calculated as follows: \[ \vec{A} \cdot \vec{B} = (5\hat{i} + 7\hat{j} - 3\hat{k}) \cdot (2\hat{i} + 2\hat{j} - a\hat{k}) \] Using the distributive property of the dot product: \[ = 5 \cdot 2 + 7 \cdot 2 + (-3) \cdot (-a) \] \[ = 10 + 14 + 3a \] \[ = 24 + 3a \] ### Step 4: Set the dot product equal to zero Since the vectors are perpendicular: \[ 24 + 3a = 0 \] ### Step 5: Solve for \( a \) Rearranging the equation gives: \[ 3a = -24 \] \[ a = \frac{-24}{3} \] \[ a = -8 \] ### Conclusion The value of \( a \) is \( -8 \). ---
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VMC MODULES ENGLISH-BASIC MATHEMATICS & VECTORS-Enable
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