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The ratio of maximum and minimum magnitu...

The ratio of maximum and minimum magnitudes of the resultant of two vectors `vec(a)` and `vec(b)` is 3:1. Now, `|vec(a)|` is equal to

A

`|vec(b)|`

B

`2|vec(b)|`

C

`3|vec(b)|`

D

`4|vec(b)|`

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To solve the problem, we need to find the magnitude of vector \( \vec{a} \) given that the ratio of the maximum and minimum magnitudes of the resultant of two vectors \( \vec{a} \) and \( \vec{b} \) is 3:1. ### Step-by-Step Solution: 1. **Understanding the Resultant of Two Vectors**: The resultant \( R \) of two vectors \( \vec{a} \) and \( \vec{b} \) can be expressed using the formula: \[ R = \sqrt{|\vec{a}|^2 + |\vec{b}|^2 + 2 |\vec{a}| |\vec{b}| \cos \theta} \] where \( \theta \) is the angle between the two vectors. 2. **Finding Maximum Resultant**: The maximum resultant occurs when \( \cos \theta = 1 \) (i.e., when the vectors are in the same direction, \( \theta = 0^\circ \)): \[ R_{\text{max}} = |\vec{a}| + |\vec{b}| \] 3. **Finding Minimum Resultant**: The minimum resultant occurs when \( \cos \theta = -1 \) (i.e., when the vectors are in opposite directions, \( \theta = 180^\circ \)): \[ R_{\text{min}} = ||\vec{a}| - |\vec{b}|| = ||a| - |b|| \] 4. **Setting Up the Ratio**: According to the problem, the ratio of the maximum to minimum resultant is given as: \[ \frac{R_{\text{max}}}{R_{\text{min}}} = \frac{3}{1} \] Substituting the expressions for \( R_{\text{max}} \) and \( R_{\text{min}} \): \[ \frac{|\vec{a}| + |\vec{b}|}{||\vec{a}| - |\vec{b}||} = 3 \] 5. **Cross-Multiplying**: Cross-multiplying gives: \[ |\vec{a}| + |\vec{b}| = 3 \cdot ||\vec{a}| - |\vec{b}|| \] 6. **Considering Cases**: We can consider two cases based on the magnitudes of \( |\vec{a}| \) and \( |\vec{b}| \): - Case 1: \( |\vec{a}| \geq |\vec{b}| \) \[ |\vec{a}| + |\vec{b}| = 3 (|\vec{a}| - |\vec{b}|) \] Simplifying this: \[ |\vec{a}| + |\vec{b}| = 3|\vec{a}| - 3|\vec{b}| \] \[ 4|\vec{b}| = 2|\vec{a}| \] \[ |\vec{a}| = 2|\vec{b}| \] - Case 2: \( |\vec{a}| < |\vec{b}| \) \[ |\vec{a}| + |\vec{b}| = 3 (|\vec{b}| - |\vec{a}|) \] This case will lead to a contradiction since it will imply \( |\vec{a}| \) cannot be less than \( |\vec{b}| \) based on the ratio given. 7. **Conclusion**: Thus, from Case 1, we conclude that: \[ |\vec{a}| = 2|\vec{b}| \] ### Final Answer: The magnitude of vector \( \vec{a} \) is \( 2|\vec{b}| \).
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