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The resultant of barP and barQ is perpe...

The resultant of `barP` and `barQ` is perpendicular to `barP` . What is the angle between `barP` and `barQ` :

A

`cos^(-1)((A)/(B))`

B

`cos^(-1)(-(A)/(B))`

C

`sin^(-1)((A)/(B))`

D

`sin^(-1)(-(A)/(B))`

Text Solution

Verified by Experts

The correct Answer is:
B
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