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Three forces A = (hat(i) + hat(j) + hat(...

Three forces `A = (hat(i) + hat(j) + hat(k)), B = (2hat(i) - hat(j) + 3hat(k))` and C acting on a body to keep it in equilibrium. The C is :

A

`-(3hat(i) + 4hat(k))`

B

`-(4hat(i) + 3hat(k))`

C

`3hat(i) + 4hat(k)`

D

`2hat(i) - 3hat(k)`

Text Solution

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The correct Answer is:
To find the force vector \( \mathbf{C} \) that keeps the body in equilibrium, we can follow these steps: ### Step 1: Understand the condition for equilibrium For a body to be in equilibrium, the vector sum of all forces acting on it must equal zero. This can be expressed mathematically as: \[ \mathbf{A} + \mathbf{B} + \mathbf{C} = \mathbf{0} \] ### Step 2: Write down the given forces We have the following forces: - \( \mathbf{A} = \hat{i} + \hat{j} + \hat{k} \) - \( \mathbf{B} = 2\hat{i} - \hat{j} + 3\hat{k} \) ### Step 3: Substitute the forces into the equilibrium equation Substituting the values of \( \mathbf{A} \) and \( \mathbf{B} \) into the equilibrium equation gives: \[ (\hat{i} + \hat{j} + \hat{k}) + (2\hat{i} - \hat{j} + 3\hat{k}) + \mathbf{C} = \mathbf{0} \] ### Step 4: Combine the forces \( \mathbf{A} \) and \( \mathbf{B} \) Now, we can combine the components of \( \mathbf{A} \) and \( \mathbf{B} \): - For \( \hat{i} \): \( 1 + 2 = 3\hat{i} \) - For \( \hat{j} \): \( 1 - 1 = 0\hat{j} \) - For \( \hat{k} \): \( 1 + 3 = 4\hat{k} \) Thus, we have: \[ 3\hat{i} + 0\hat{j} + 4\hat{k} + \mathbf{C} = \mathbf{0} \] ### Step 5: Isolate \( \mathbf{C} \) To find \( \mathbf{C} \), we can rearrange the equation: \[ \mathbf{C} = - (3\hat{i} + 0\hat{j} + 4\hat{k}) \] This simplifies to: \[ \mathbf{C} = -3\hat{i} - 4\hat{k} \] ### Step 6: Write the final answer Thus, the force vector \( \mathbf{C} \) that keeps the body in equilibrium is: \[ \mathbf{C} = -3\hat{i} - 4\hat{k} \]
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