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A train of length 200 m traveling at 30 ...

A train of length 200 m traveling at `30 ms ^(-1)` overtakes another train of length 300 m traveling at `20 ms ^(-1).` The time taken by the first train to pass the second is

A

10 s

B

30 s

C

40 s

D

50 s

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The correct Answer is:
To solve the problem of how long it takes for the first train to overtake the second train, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the lengths of the trains and their speeds:** - Length of the first train (Train 1), \( L_1 = 200 \, m \) - Length of the second train (Train 2), \( L_2 = 300 \, m \) - Speed of Train 1, \( V_1 = 30 \, m/s \) - Speed of Train 2, \( V_2 = 20 \, m/s \) 2. **Calculate the relative velocity:** - Since Train 1 is overtaking Train 2, we need to find the relative velocity of Train 1 with respect to Train 2. - The formula for relative velocity when two objects are moving in the same direction is: \[ V_{relative} = V_1 - V_2 \] - Substituting the values: \[ V_{relative} = 30 \, m/s - 20 \, m/s = 10 \, m/s \] 3. **Calculate the total distance to be covered:** - The total distance that Train 1 needs to cover to completely overtake Train 2 is the sum of the lengths of both trains: \[ \text{Total Distance} = L_1 + L_2 = 200 \, m + 300 \, m = 500 \, m \] 4. **Calculate the time taken to overtake:** - The time taken to overtake can be calculated using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Relative Velocity}} \] - Substituting the values: \[ \text{Time} = \frac{500 \, m}{10 \, m/s} = 50 \, s \] 5. **Conclusion:** - Therefore, the time taken by the first train to pass the second train is \( 50 \, seconds \).
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