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An object moving with a speed of 6.25 m...

An object moving with a speed of `6.25 m//s ` is declerated at a rate given by ` (dv)/( dt) =-2.5sqrtv` where v is instantaneous speed . The times taken by the object , to come to rest ,would be:

A

1s

B

2s

C

4s

D

8s

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The correct Answer is:
A
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VMC MODULES ENGLISH-MOTION IN A STRAIGHT LINE & PLANE -ENABLE
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