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An athelete completes one round of a cir...

An athelete completes one round of a circular track of radius `R` in 40 seconds. What will be the displacement at the end of ` 2 min. 20 second ?

A

zero

B

2R

C

`2piR`

D

`7pR`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the displacement of the athlete after completing a certain amount of time on a circular track. ### Step-by-Step Solution: 1. **Convert the total time into seconds:** - The total time given is 2 minutes and 20 seconds. - Convert 2 minutes into seconds: \[ 2 \text{ minutes} = 2 \times 60 = 120 \text{ seconds} \] - Add the remaining 20 seconds: \[ \text{Total time} = 120 \text{ seconds} + 20 \text{ seconds} = 140 \text{ seconds} \] 2. **Determine the number of complete rounds:** - The athlete completes one round of the circular track in 40 seconds. - To find the number of complete rounds in 140 seconds, divide the total time by the time per round: \[ \text{Number of rounds} = \frac{140 \text{ seconds}}{40 \text{ seconds/round}} = 3.5 \text{ rounds} \] 3. **Identify the position after 3 complete rounds:** - After completing 3 rounds, the athlete will be back at the starting point on the circular track. 4. **Calculate the position after the additional 0.5 round:** - After completing 3 rounds (which takes 120 seconds), the athlete has 20 seconds left. - In 20 seconds, the athlete covers half a round (since 20 seconds is half of 40 seconds). - Starting from the initial position (let's say point A), after 3 rounds, the athlete is back at point A. - After covering half a round, the athlete will be at the point directly opposite to point A (let's call this point B). 5. **Determine the displacement:** - The displacement is defined as the shortest distance from the initial position to the final position. - Since the athlete is now at point B, which is diametrically opposite to point A, the displacement is equal to the diameter of the circular track. - The diameter \(D\) of the circular track is given by: \[ D = 2R \] - Therefore, the displacement after 2 minutes and 20 seconds is \(2R\). ### Final Answer: The displacement at the end of 2 minutes and 20 seconds is \(2R\).
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