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A particle has a velocity u towards east...

A particle has a velocity u towards east at `t = 0`. Its acceleration is towards west and is constant. Let `x_(A)` and `x_(B)` be the magnitude of displacement in the first 10 seconds and the next 10 seconds:

A

`x _(A) lt x _(B)`

B

`x _(A) =x_(B)`

C

`x_(A) gt x_(B)`

D

the information is insufficient to decide the ralation of `x _(A) and x _(B)`

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The correct Answer is:
To solve the problem, we need to find the displacements \( x_A \) and \( x_B \) for a particle moving with an initial velocity \( u \) towards the east and a constant acceleration \( a \) towards the west. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle starts with an initial velocity \( u \) towards the east. - The acceleration \( a \) is constant and directed towards the west (opposite to the direction of the initial velocity). 2. **Displacement in the First 10 Seconds**: - We use the second equation of motion: \[ s = ut + \frac{1}{2} a t^2 \] - For the first 10 seconds (\( t = 10 \) seconds): \[ x_A = u \cdot 10 + \frac{1}{2} (-a) \cdot (10)^2 \] - Simplifying this gives: \[ x_A = 10u - 50a \] - This is our **Equation 1**. 3. **Displacement in the Next 10 Seconds**: - For the next 10 seconds, the total time is now 20 seconds. - Using the same equation of motion: \[ x_B = u \cdot 20 + \frac{1}{2} (-a) \cdot (20)^2 \] - Simplifying this gives: \[ x_B = 20u - 200a \] - This is our **Equation 2**. 4. **Finding the Displacement for the Next 10 Seconds**: - The displacement \( x_B \) for the next 10 seconds can also be expressed as: \[ x_B = x_{total} - x_A \] - The total displacement after 20 seconds is: \[ x_{total} = x_B = 20u - 200a \] - Therefore: \[ x_B = (20u - 200a) - (10u - 50a) \] - Simplifying this gives: \[ x_B = 10u - 150a \] 5. **Comparing \( x_A \) and \( x_B \)**: - We have: \[ x_A = 10u - 50a \quad \text{(from Equation 1)} \] \[ x_B = 10u - 150a \quad \text{(from Equation 3)} \] - To compare \( x_A \) and \( x_B \): - Subtract \( x_B \) from \( x_A \): \[ x_A - x_B = (10u - 50a) - (10u - 150a) = 100a \] - Since \( a \) is positive (acceleration towards the west), \( x_A > x_B \). ### Conclusion: Thus, the relationship between the displacements is: \[ x_A > x_B \] ### Final Answer: The correct option is that \( x_A \) is greater than \( x_B \).
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