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Which of the following pairs does not ha...

Which of the following pairs does not have similar dimensions ?

A

Tension and surface tension

B

Stress and pressure

C

Plank's constant and angular momentum

D

Angle and strain

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of identifying which pair of quantities does not have similar dimensions, we will analyze the dimensions of each pair provided in the question. ### Step-by-Step Solution: 1. **Identify the quantities in the first pair: Tension and Surface Tension.** - **Surface Tension (T)**: - Surface tension is defined as force per unit length. - Force can be expressed as mass times acceleration (F = ma). - Acceleration can be expressed in terms of velocity (v) and time (t): a = v/t. - Therefore, the dimension of force is: \[ [F] = [M][L][T^{-2}] = MLT^{-2} \] - Now, surface tension is: \[ [\text{Surface Tension}] = \frac{[F]}{[\text{Length}]} = \frac{MLT^{-2}}{L} = MT^{-2} \] - **Tension**: - Tension is defined as the magnitude of force, hence: \[ [\text{Tension}] = [F] = MLT^{-2} \] - **Conclusion for Pair 1**: - Dimensions of Surface Tension: \( MT^{-2} \) - Dimensions of Tension: \( MLT^{-2} \) - Since \( MT^{-2} \) is not equal to \( MLT^{-2} \), these two do not have similar dimensions. 2. **Identify the quantities in the second pair: Stress and Pressure.** - **Stress**: - Stress is defined as force per unit area. - Therefore, the dimension of stress is: \[ [\text{Stress}] = \frac{[F]}{[\text{Area}]} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} \] - **Pressure**: - Pressure is also defined as force per unit area, hence: \[ [\text{Pressure}] = \frac{[F]}{[\text{Area}]} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} \] - **Conclusion for Pair 2**: - Both Stress and Pressure have the same dimensions: \( ML^{-1}T^{-2} \). 3. **Identify the quantities in the third pair: Planck's Constant and Angular Momentum.** - **Planck's Constant (h)**: - It relates energy (E) and frequency (ν): \( E = hν \). - The dimension of energy is \( [E] = ML^2T^{-2} \) and frequency is \( [ν] = T^{-1} \). - Thus, the dimension of Planck's constant is: \[ [h] = \frac{[E]}{[ν]} = \frac{ML^2T^{-2}}{T^{-1}} = ML^2T^{-1} \] - **Angular Momentum (L)**: - Angular momentum is defined as \( L = mvr \) where \( m \) is mass, \( v \) is velocity, and \( r \) is radius. - The dimension of angular momentum is: \[ [L] = [M][L][T^{-1}] = ML^2T^{-1} \] - **Conclusion for Pair 3**: - Both Planck's Constant and Angular Momentum have the same dimensions: \( ML^2T^{-1} \). 4. **Identify the quantities in the fourth pair: Angle and Strain.** - **Angle**: - Angles are dimensionless quantities, often measured in radians. - Therefore, the dimension of angle is: \[ [\text{Angle}] = 1 \] - **Strain**: - Strain is defined as the ratio of change in length to original length, which is also dimensionless. - Therefore, the dimension of strain is: \[ [\text{Strain}] = 1 \] - **Conclusion for Pair 4**: - Both Angle and Strain are dimensionless quantities. ### Final Conclusion: The only pair that does not have similar dimensions is **Tension and Surface Tension**.
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