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If A = B +(C)/(D+E) the dimensions of B...

If `A = B +(C)/(D+E)` the dimensions of B and C are `[M^(0)L T^(-1)]` and `[M^(0)LT^(0)]` , respectively . Find the dimensions of A, D and E.

A

`A=[M^(0)L^(0)T^(-1)]`, `D=[T]`, `E=[LT]`

B

`A=[MLT^(0)]`, `D=[T^(2)]`, `E=[T^(2)]`

C

`A=[M^(0)L^(0)T^(-1)]`, `D=[MT]`, `E=[MT]`

D

`A=[M^(0)LT^(-1)]`, `D=[T]`, `E=[T]`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the dimensions of A, D, and E given the dimensions of B and C. ### Step-by-Step Solution: 1. **Identify the Given Dimensions**: - The dimension of B is given as \( [M^0 L^1 T^{-1}] \). - The dimension of C is given as \( [M^0 L^1 T^0] \). 2. **Understanding the Equation**: - The equation is given as \( A = B + \frac{C}{D + E} \). - Since we can only add quantities with the same dimensions, the dimensions of A must be the same as the dimensions of B. 3. **Determine the Dimension of A**: - Therefore, the dimension of A is: \[ [A] = [B] = [M^0 L^1 T^{-1}] \] 4. **Analyzing the Right Side of the Equation**: - The right side of the equation can be expressed as: \[ A = B + \frac{C}{D + E} \] - Since \( D + E \) must have the same dimensions for the fraction \( \frac{C}{D + E} \) to be valid, we can denote the dimension of D and E as \( [D] = [E] \). 5. **Setting Up the Equation for Dimensions**: - The dimension of \( \frac{C}{D + E} \) must also equal the dimension of A: \[ [A] = \frac{[C]}{[D + E]} \] - Since \( [D] = [E] \), we can write: \[ [D + E] = [D] + [D] = 2[D] \] 6. **Substituting the Known Dimensions**: - We know: \[ [C] = [M^0 L^1 T^0] \] - Thus, substituting into the equation gives: \[ [A] = \frac{[C]}{[D]} = \frac{[M^0 L^1 T^0]}{[D]} \] 7. **Equating the Dimensions**: - We already found that \( [A] = [M^0 L^1 T^{-1}] \): \[ [M^0 L^1 T^{-1}] = \frac{[M^0 L^1 T^0]}{[D]} \] - Rearranging gives: \[ [D] = \frac{[M^0 L^1 T^0]}{[M^0 L^1 T^{-1}]} = [T^1] \] 8. **Conclusion**: - Thus, the dimensions are: - \( [A] = [M^0 L^1 T^{-1}] \) - \( [D] = [T^1] \) - Since \( [D] = [E] \), we also have \( [E] = [T^1] \). ### Final Dimensions: - \( [A] = [M^0 L^1 T^{-1}] \) - \( [D] = [T^1] \) - \( [E] = [T^1] \)
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