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If energy of photon is Eproph^(a)c^(b)la...

If energy of photon is `Eproph^(a)c^(b)lamda^(d)`.
Here `h=` Planck's constant `c=` speed of light and
`lamda=` wavelength of photon
Then, the value of `a,b` and `d` are

A

`1,1,1`

B

`1,-1,1`

C

``1,1,-1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
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