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The dimensional formula for specific hea...

The dimensional formula for specific heat is

A

(a)`M^(0)L^(2)T^(-2)`

B

(b)`M^(1)L^(2)T^(-2)K^(-1)`

C

(c)`M^(0)L^(2)T^(-2)K^(-1)`

D

(d)`M^(1)L^(2)T^(-2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula for specific heat, we can follow these steps: ### Step 1: Understand the definition of specific heat Specific heat (denoted as \( s \)) is defined as the amount of heat \( Q \) required to raise the temperature of a unit mass \( m \) of a substance by 1 degree Celsius (or 1 Kelvin). Mathematically, it can be expressed as: \[ s = \frac{Q}{m \cdot \Delta T} \] where \( \Delta T \) is the change in temperature. ### Step 2: Identify the dimensions of heat \( Q \) The amount of heat \( Q \) can be expressed in terms of its dimensional formula. The dimensional formula for heat is derived from the formula for energy, which is: \[ Q = m \cdot a \cdot d \] where \( m \) is mass, \( a \) is acceleration, and \( d \) is distance. The dimensional formula for heat is: \[ [Q] = M^1 L^2 T^{-2} \] ### Step 3: Identify the dimensions of mass \( m \) The dimensional formula for mass \( m \) is simply: \[ [m] = M^1 \] ### Step 4: Identify the dimensions of temperature change \( \Delta T \) The change in temperature \( \Delta T \) is measured in Kelvin (K), and its dimensional formula is: \[ [\Delta T] = K^1 \] ### Step 5: Substitute the dimensions into the specific heat formula Now, substituting the dimensions into the specific heat formula: \[ s = \frac{[Q]}{[m] \cdot [\Delta T]} = \frac{M^1 L^2 T^{-2}}{M^1 \cdot K^1} \] ### Step 6: Simplify the expression Now, simplifying the expression: \[ s = \frac{M^1 L^2 T^{-2}}{M^1 K^1} = M^{1-1} L^2 T^{-2} K^{-1} = M^0 L^2 T^{-2} K^{-1} \] ### Step 7: Write the final dimensional formula Thus, the final dimensional formula for specific heat is: \[ [M^0 L^2 T^{-2} K^{-1}] \] ### Step 8: Identify the correct option Now, we can check the options provided in the question. The correct option corresponding to the dimensional formula \( M^0 L^2 T^{-2} K^{-1} \) is option C. ---
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