Home
Class 12
PHYSICS
The dimensions of mu(0) are...

The dimensions of `mu_(0)` are

A

`M^(2)L^(-2)T^(-2)`

B

`M^(0)L^(0)T^(0)`

C

`M^(1)L^(1)T^(-2)`

D

`M^(1)L^(1)T`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • UNITS, MEASUREMENTS & ERRORS

    VMC MODULES ENGLISH|Exercise Efficient|50 Videos

  • UNITS, MEASUREMENTS & ERRORS

    VMC MODULES ENGLISH|Exercise Impeccable|51 Videos

  • UNITS, MEASUREMENTS & ERRORS

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - B|10 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|56 Videos

  • WAVE MOTION

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE LEVEL 2 (TRUE FALSE TYPE)|4 Videos

Similar Questions

Explore conceptually related problems

The dimensions of (mu_(0)epsilon_(0))^(-1//2) are

The dimensional formula mu_(0)epsilon_0 is

The dimensions of epsilon_(0)mu_(0) are

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

If discharge rate is given by V=(pi Pr^(4))/(8 mu l) then find out the dimensions of mu by taking velocity (v), time (T) and mass (M) as fundamental units.

If A = B +(C)/(D+E) the dimensions of B and C are [M^(0)L T^(-1)] and [M^(0)LT^(0)] , respectively . Find the dimensions of A, D and E.

Find the dimension of B^2/(2 mu_0)

The dimensions of (1)/(sqrt(mu_(0)epsi_(0))) are the same as that of

The dimension of (B^(2))/(2mu_(0)), where B is magnetic field and mu_(0) is the magnetic permeability of vacuum, is :