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A small steel ball of radius r is allowe...

A small steel ball of radius r is allowed to fall under gravity through a column of a viscous liquid of coefficient of viscosity `eta`. After some time the velocity of the ball attains a constant value known as terminal velocity `upsilon_T`. The terminal velocity depends on (i) the mass of the ball m (ii) `eta`, (iii) r and (iv) acceleration due to gravity g . Which of the following relations is dimensionally correct?

A

`v_(T) prop (mg)/(eta r)`

B

`v_(T) prop (etar)/(mg)`

C

`v_(T) prop eta r mg`

D

`v_(T) prop (mgr)/(eta)`

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To solve the problem of determining which relation for terminal velocity \( \upsilon_T \) is dimensionally correct, we will analyze the dependencies on mass \( m \), viscosity \( \eta \), radius \( r \), and acceleration due to gravity \( g \). ### Step 1: Identify the dimensions of the variables involved 1. **Mass \( m \)**: The dimension of mass is \( [M] \). 2. **Viscosity \( \eta \)**: The dimension of viscosity can be derived from the equation of viscous force: \[ F = \eta A \frac{dv}{dx} \] - Force \( F \): \( [F] = [M][L][T^{-2}] = [MLT^{-2}] \) - Area \( A \): \( [A] = [L^2] \) - Change in velocity \( dv \): \( [dv] = [LT^{-1}] \) - Change in distance \( dx \): \( [dx] = [L] \) Rearranging gives: \[ \eta = \frac{F}{A \frac{dv}{dx}} = \frac{[MLT^{-2}]}{[L^2] \cdot [LT^{-1}]/[L]} = [ML^{-1}T^{-1}] \] 3. **Radius \( r \)**: The dimension of radius is \( [L] \). 4. **Acceleration due to gravity \( g \)**: The dimension of acceleration is \( [g] = [LT^{-2}] \). ### Step 2: Determine the dimension of terminal velocity \( \upsilon_T \) The dimension of terminal velocity is: \[ [\upsilon_T] = [LT^{-1}] \] ### Step 3: Analyze each option for dimensional correctness 1. **Option A**: \( \upsilon_T \propto \frac{mg}{\eta r} \) - Dimensions: \[ [mg] = [M][LT^{-2}] = [MLT^{-2}] \] \[ [\eta] = [ML^{-1}T^{-1}] \] \[ [r] = [L] \] - Therefore: \[ \frac{mg}{\eta r} = \frac{[MLT^{-2}]}{[ML^{-1}T^{-1}][L]} = \frac{[MLT^{-2}]}{[MLT^{-1}]} = [LT^{-1}] \] - This matches the dimension of velocity \( [LT^{-1}] \). **Option A is correct**. 2. **Option B**: \( \upsilon_T \propto \frac{1}{\frac{mg}{\eta r}} \) - This would give dimensions of \( [LT^{-1}]^{-1} \), which does not match \( [LT^{-1}] \). **Option B is incorrect**. 3. **Option C**: \( \upsilon_T \propto \eta r mg \) - Dimensions: \[ [\eta r mg] = [ML^{-1}T^{-1}][L][MLT^{-2}] = [M^2L^2T^{-3}] \] - This does not match \( [LT^{-1}] \). **Option C is incorrect**. 4. **Option D**: \( \upsilon_T \propto \frac{mg}{\eta r^2} \) - Dimensions: \[ \frac{mg}{\eta r^2} = \frac{[MLT^{-2}]}{[ML^{-1}T^{-1}][L^2]} = \frac{[MLT^{-2}]}{[ML^{-1}T^{-1}]} = [LT^{-1}] \] - This matches the dimension of velocity \( [LT^{-1}] \). **Option D is also correct**. ### Conclusion The dimensionally correct relations for terminal velocity \( \upsilon_T \) are found in **Option A** and **Option D**.
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