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Inductance L can be dimensional represen...

Inductance L can be dimensional represented as

A

`ML^(2)T^(-2)A^(-1)`

B

`ML^(2)T^(-4)A^(-3)`

C

`ML^(-2)T^(-2)A^(-2)`

D

`ML^(2)T^(4)A^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional representation of inductance \( L \), we can follow these steps: ### Step 1: Understand the relationship involving inductance Inductance \( L \) is related to the inductive reactance \( X_L \), which can be expressed as: \[ X_L = \frac{V}{I} \] where \( V \) is voltage and \( I \) is current. ### Step 2: Write the dimensional formula for voltage \( V \) Voltage \( V \) can be expressed in terms of work \( W \) and charge \( Q \): \[ V = \frac{W}{Q} \] The dimensional formula for work \( W \) is: \[ W = ML^2T^{-2} \] And the dimensional formula for charge \( Q \) is: \[ Q = IT = AT \] where \( A \) is the unit of current. ### Step 3: Substitute the dimensional formulas into the voltage equation Now substituting these into the voltage equation: \[ V = \frac{ML^2T^{-2}}{AT} \] This gives us: \[ V = ML^2T^{-3}A^{-1} \] ### Step 4: Write the dimensional formula for current \( I \) The dimensional formula for current \( I \) is simply: \[ I = A \] ### Step 5: Find the dimensional formula for inductive reactance \( X_L \) Now substituting the dimensional formulas for \( V \) and \( I \) into the equation for \( X_L \): \[ X_L = \frac{V}{I} = \frac{ML^2T^{-3}A^{-1}}{A} = ML^2T^{-3}A^{-2} \] ### Step 6: Relate inductive reactance \( X_L \) to inductance \( L \) The inductive reactance \( X_L \) is also related to inductance \( L \) and angular frequency \( \omega \): \[ X_L = \omega L \] where \( \omega \) has the dimensional formula: \[ \omega = \frac{2\pi}{T} \quad \text{(dimensionally, it is } T^{-1}\text{)} \] ### Step 7: Rearranging to find the dimensional formula for \( L \) From the equation \( X_L = \omega L \), we can express \( L \) as: \[ L = \frac{X_L}{\omega} \] Substituting the dimensional formulas: \[ L = \frac{ML^2T^{-3}A^{-2}}{T^{-1}} = ML^2T^{-2}A^{-2} \] ### Conclusion Thus, the dimensional representation of inductance \( L \) is: \[ [L] = ML^2T^{-2}A^{-2} \] ### Final Answer The correct option is \( ML^2T^{-2}A^{-2} \). ---
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