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If L,C and R denote the inductance, capa...

If `L,C` and `R` denote the inductance, capacitance and resistance respectively, the dimensional formula for `C^(2)LR` is

A

`[ML^(-2)T^(-1)I^(0)]`

B

`[M^(0)L^(0)T^(3)I^(0)]`

C

`[M^(-1)L^(-2)T^(6)I^(2)]`

D

`[M^(0)L^(0)T^(2)I^(0)]`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula for \( C^2LR \), where \( L \) is inductance, \( C \) is capacitance, and \( R \) is resistance, we will derive the dimensions of each component and then combine them accordingly. ### Step-by-Step Solution: 1. **Identify the dimensions of each component:** - The dimensional formula for **inductance (L)** is given by: \[ [L] = [M^1 L^2 T^{-2} I^{-2}] \] - The dimensional formula for **capacitance (C)** is given by: \[ [C] = [M^{-1} L^{-2} T^4 I^2] \] - The dimensional formula for **resistance (R)** is given by: \[ [R] = [M^1 L^2 T^{-3} I^{-2}] \] 2. **Calculate \( C^2 \):** - To find the dimensions of \( C^2 \): \[ [C^2] = ([C])^2 = [M^{-1} L^{-2} T^4 I^2]^2 = [M^{-2} L^{-4} T^8 I^4] \] 3. **Combine the dimensions of \( C^2 \), \( L \), and \( R \):** - Now we will combine the dimensions: \[ [C^2LR] = [C^2] \cdot [L] \cdot [R] \] - Substitute the dimensional formulas: \[ [C^2LR] = [M^{-2} L^{-4} T^8 I^4] \cdot [M^1 L^2 T^{-2} I^{-2}] \cdot [M^1 L^2 T^{-3} I^{-2}] \] 4. **Combine the dimensions step by step:** - First, combine \( [C^2] \) and \( [L] \): \[ [C^2L] = [M^{-2} L^{-4} T^8 I^4] \cdot [M^1 L^2 T^{-2} I^{-2}] = [M^{-1} L^{-2} T^6 I^2] \] - Now combine this result with \( [R] \): \[ [C^2LR] = [M^{-1} L^{-2} T^6 I^2] \cdot [M^1 L^2 T^{-3} I^{-2}] = [M^{0} L^{0} T^{3} I^{0}] = [T^3] \] 5. **Final Result:** - The dimensional formula for \( C^2LR \) is: \[ [C^2LR] = [T^3] \] ### Conclusion: The dimensional formula for \( C^2LR \) is \( T^3 \).
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