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A body is under the action of two mutual...

A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

A

7N

B

1N

C

5N

D

zero

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The correct Answer is:
To find the resultant force acting on a body under the action of two mutually perpendicular forces of 3 N and 4 N, we can use the Pythagorean theorem. Here’s the step-by-step solution: ### Step 1: Identify the Forces We have two forces: - Force A = 3 N - Force B = 4 N ### Step 2: Understand the Geometry Since the forces are mutually perpendicular, we can visualize them as two sides of a right triangle, where: - One side (A) is 3 N - The other side (B) is 4 N ### Step 3: Apply the Pythagorean Theorem The resultant force (R) can be calculated using the Pythagorean theorem: \[ R = \sqrt{A^2 + B^2} \] ### Step 4: Substitute the Values Substituting the values of A and B into the equation: \[ R = \sqrt{(3 \, \text{N})^2 + (4 \, \text{N})^2} \] \[ R = \sqrt{9 \, \text{N}^2 + 16 \, \text{N}^2} \] ### Step 5: Calculate the Result Now, calculate the sum inside the square root: \[ R = \sqrt{25 \, \text{N}^2} \] \[ R = 5 \, \text{N} \] ### Conclusion The resultant force acting on the body is **5 N**. ---
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