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A force vecF=(3xN)hati+(4N)hatj, with x ...

A force `vecF=(3xN)hati+(4N)hatj`, with x in meter, acts on a particle, changing only the kinetic energy of the particle. How mcuh work is done on the particle as it moves from coordinates `(2m, 3m, 5m)` to `(3m, 0m, 6m)`? Does the speed of the particle increase, decrease, or remain the same?

A

7.5 J

B

`-12 J`

C

`-4.5 J`

D

`+4.5 J`

Text Solution

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The correct Answer is:
C
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