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A machine is delivering constant power t...

A machine is delivering constant power to drive a body along a straight line. What is the relation between the distance travelled by the body against time ?

A

(a)`s^(2)alpha t^(3)`

B

(b)`s^(2)alpha t^(3)`

C

(c)`s^(3)alpha t^(2)`

D

(d)`s alpha t^(3)`

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The correct Answer is:
To solve the problem of finding the relationship between the distance traveled by a body and time when a machine delivers constant power, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Power Equation**: We know that power (P) is defined as the product of force (F) and velocity (v): \[ P = F \cdot v \] 2. **Express Force in Terms of Mass and Acceleration**: The force can be expressed using Newton's second law: \[ F = m \cdot a \] where \( m \) is the mass of the body and \( a \) is its acceleration. 3. **Relate Acceleration to Distance and Time**: Acceleration can also be expressed as the change in velocity over time. If we consider distance (s) traveled in time (t), we can express acceleration as: \[ a = \frac{s}{t^2} \] This is derived from the kinematic equation \( s = \frac{1}{2} a t^2 \) when starting from rest. 4. **Substitute Acceleration into the Power Equation**: Now, substituting \( F \) and \( v \) into the power equation: - Velocity \( v \) can be expressed as \( v = \frac{s}{t} \). - Therefore, substituting \( F \) and \( v \): \[ P = (m \cdot a) \cdot v = m \cdot \left(\frac{s}{t^2}\right) \cdot \left(\frac{s}{t}\right) \] Simplifying this gives: \[ P = m \cdot \frac{s^2}{t^3} \] 5. **Rearranging the Equation**: Since power (P) is constant, we can rearrange the equation to find the relationship between distance and time: \[ s^2 = \frac{P \cdot t^3}{m} \] This shows that \( s^2 \) is directly proportional to \( t^3 \): \[ s^2 \propto t^3 \] 6. **Conclusion**: The relationship between the distance traveled (s) and time (t) is: \[ s^2 = k \cdot t^3 \] where \( k = \frac{P}{m} \) is a constant. ### Final Relation: Thus, we conclude that the distance squared is directly proportional to the cube of time: \[ s^2 \propto t^3 \]
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