Home
Class 12
PHYSICS
A circular loop of radius R , carrying I...

A circular loop of radius `R` , carrying `I`, lies in `x- y` plane with its origin . The total magnetic flux through ` x-y` plane is

A

Directly proportional to R

B

Directly proportional to I

C

Inversely proportional to I

D

Zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the total magnetic flux through the x-y plane due to a circular loop of radius \( R \) carrying a current \( I \), we can follow these steps: ### Step 1: Understand the Magnetic Field due to the Circular Loop A circular loop carrying a current generates a magnetic field around it. The direction of the magnetic field can be determined using the right-hand rule. For a loop lying in the x-y plane, the magnetic field lines will emerge from the loop's center and form closed loops around the wire. ### Step 2: Analyze the Magnetic Field Lines The magnetic field lines created by the current in the loop will enter the x-y plane at some points and exit at others, forming closed loops. This means that for every magnetic field line entering the x-y plane, there is a corresponding line exiting the plane. ### Step 3: Calculate the Magnetic Flux Magnetic flux (\( \Phi_B \)) through a surface is given by the formula: \[ \Phi_B = \int \vec{B} \cdot d\vec{A} \] where \( \vec{B} \) is the magnetic field and \( d\vec{A} \) is the differential area vector. ### Step 4: Consider the Orientation of the Area Vector In this case, the area vector \( d\vec{A} \) for the x-y plane points in the z-direction. However, the magnetic field lines due to the loop are oriented in such a way that they enter and exit the x-y plane, resulting in equal contributions of magnetic field entering and exiting the plane. ### Step 5: Conclude the Total Magnetic Flux Since the magnetic field lines that enter the x-y plane are equal in magnitude and opposite in direction to those that exit, the total magnetic flux through the x-y plane sums to zero. Therefore, the total magnetic flux through the x-y plane is: \[ \Phi_B = 0 \] ### Final Answer The total magnetic flux through the x-y plane is \( 0 \). ---
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES & MAGNETISM

    VMC MODULES ENGLISH|Exercise ENABLE|50 Videos
  • MOVING CHARGES & MAGNETISM

    VMC MODULES ENGLISH|Exercise EFFICIENT|50 Videos
  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos
  • PROPERTIES OF MATTER

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive) Level - 2 (MATRIX MATCH TYPE)|1 Videos

Similar Questions

Explore conceptually related problems

(A) : A circular loop carrying current lies in XY plane with its centre at origin will have a magnetic flux in negative Z-axis. (R) : Magnetic flux direction is independent of the direction of current in conductor.

A circular coil, carrying a constant current i s kept in the x - y plane. The magnetic flux through the entire x - y plane exluding the area of the circular coil is given by phi and the magetic flux through the area of the circular coil area is given by phi_(0) , then

A current carrying circular loop of radius R is placed in the x-y plane with centre at the origin. Half of the loop with xgt0 is now bent so that it now lies in the y-z plane.

A current carrying circular loop of radius R is placed in the x-y plane with centre at the origin. Half of the loop with xgt0 is now bent so that it now lies in the y-z plane.

A hypthetical magnetic field existing in a region is given by vecB= B_0 vece_r, where vec_r denotes the uit vector along the redial direction. A circular loop of radus a, carrying a current I, is placed with its plane parallel to the x-y plane and the centre at (0,0, d) .Find the magnitude of the magnetic force acting on the loop.

A current - carrying circular loop of radius R is placed in the XY- plane with centre at the origin. Half of the loop with xgt0 is now bent so that is now lies in the YZ- plane

A circular wire loop of radius R is placed in the X-Y plane with its centre at the origin. The loop carries a current I in the clockwise direction when viewed from a point on the positive Z-axis. A uniform magnetic field vecB=B_(0)((hati+sqrt(3)hatj)/2) exists in the region x gt (R sqrt(3))/2 . The magnitued of the magnetic force on the loop due to the magnetic field is (B_(0)IR)/n . The value of n is______________.

Consider a circular coil of wire carrying constant current I, forming a magnetic dipole. The magnetic flux through an infinite plane that contains the circular coil and excluding the circular area is given by phi . magnetic flux through the area of the circular area is given by phi . Which of the following option is correct?

A uniform disc of radius R lies in x-y plane with its centre at origin. Its moment of inertia about the axis x=2R and y=0 is equal to the moment of inertia about the axis y=d and z=0, where d is equal to

A circular loop of radius r carrying a current i is held at the centre of another circular loop of radius R(>> r) carrying a current I. The plane of the smaller loop makes an angle of 30^@ with that of the larger loop. It the smaller loop is held fixed in this position by applying a single force at a point on its periphery, what would be the minimum magnitude of this force?