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The magnetic field midway between two pa...

The magnetic field midway between two parallel current carrying wires, carrying currents I and 2i in same direction is B. If the current in the wire with current I is switched off, the magnetic field will become

A

`B//3`

B

`2B`

C

`B//2`

D

`B//4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the magnetic fields produced by two parallel current-carrying wires and how the magnetic field changes when one of the currents is turned off. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two parallel wires. Wire 1 carries a current \( I \) and Wire 2 carries a current \( 2I \). Both currents are in the same direction. - We need to find the magnetic field at the midpoint between these two wires. 2. **Magnetic Field Due to a Long Straight Current-Carrying Wire**: - The magnetic field \( B \) at a distance \( r \) from a long straight wire carrying current \( I \) is given by: \[ B = \frac{\mu_0 I}{2\pi r} \] - For Wire 1 (current \( I \)): \[ B_1 = \frac{\mu_0 I}{2\pi r} \] - For Wire 2 (current \( 2I \)): \[ B_2 = \frac{\mu_0 (2I)}{2\pi r} = \frac{2\mu_0 I}{2\pi r} = \frac{\mu_0 I}{\pi r} \] 3. **Direction of the Magnetic Fields**: - Using the right-hand rule, the magnetic field due to Wire 1 (\( B_1 \)) at the midpoint will be directed into the plane of the paper. - The magnetic field due to Wire 2 (\( B_2 \)) will be directed out of the plane of the paper. 4. **Net Magnetic Field at the Midpoint**: - Since \( B_1 \) is into the plane and \( B_2 \) is out of the plane, the net magnetic field \( B \) at the midpoint is: \[ B = B_2 - B_1 = \frac{\mu_0 I}{\pi r} - \frac{\mu_0 I}{2\pi r} \] - Simplifying this: \[ B = \frac{\mu_0 I}{\pi r} - \frac{\mu_0 I}{2\pi r} = \frac{2\mu_0 I}{2\pi r} - \frac{\mu_0 I}{2\pi r} = \frac{\mu_0 I}{2\pi r} = B \] 5. **Switching Off the Current in Wire 1**: - When the current \( I \) in Wire 1 is switched off, the magnetic field at the midpoint will only be due to Wire 2: \[ B' = B_2 = \frac{\mu_0 (2I)}{2\pi r} = \frac{2\mu_0 I}{2\pi r} = 2B \] 6. **Conclusion**: - Therefore, when the current in Wire 1 is switched off, the magnetic field at the midpoint becomes: \[ B' = 2B \] ### Final Answer: The magnetic field will become \( 2B \). ---
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