1 charge of `1C` in a magnetic field of `0.5` Tesla with a velocity of `10m//sec` Perpendicular to the field. Force experienced is

Options

A. 5 N
B. 10 N
C. 0.5 N
D. 0 N

Answer

To solve the problem of finding the force experienced by a charge moving in a magnetic field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Charge (Q) = 1 Coulomb
- Magnetic Field (B) = 0.5 Tesla
- Velocity (V) = 10 m/s
- Angle (θ) = 90 degrees (since the velocity is perpendicular to the magnetic field)

2. **Use the Formula for Magnetic Force**:
The force (F) experienced by a charge moving in a magnetic field is given by the formula:
\[ F = Q \cdot V \cdot B \cdot \sin(\theta) \]

3. **Substitute the Values into the Formula**:
Since θ = 90 degrees, we know that \(\sin(90^\circ) = 1\). Therefore, we can simplify the equation:
\[ F = 1 \cdot 10 \cdot 0.5 \cdot \sin(90^\circ) \]
\[ F = 1 \cdot 10 \cdot 0.5 \cdot 1 \]

4. **Calculate the Force**:
\[ F = 1 \cdot 10 \cdot 0.5 = 5 \text{ Newtons} \]

5. **Conclusion**:
The force experienced by the charge is **5 Newtons**.