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Two bar magnets of the same mass, length...

Two bar magnets of the same mass, length and breadth but magnetic moment M and 2M respectively, when placed in same position, time period is 3 sec. What will be the time period when they are placed in different position?

A

`sqrt(3)sec`

B

`3sqrt(3)sec`

C

3 sec

D

6 sec

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the time period of two bar magnets with different magnetic moments when placed in different positions. Let's break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We have two bar magnets with magnetic moments \( M \) and \( 2M \). - When placed in the same position, the time period \( T_1 \) is given as 3 seconds. 2. **Formula for Time Period**: - The time period \( T \) for two magnets in a magnetic field is given by: \[ T = 2\pi \sqrt{\frac{I_1 + I_2}{M_{\text{total}} \cdot B}} \] - Where \( I_1 \) and \( I_2 \) are the moments of inertia of the magnets, \( M_{\text{total}} \) is the total magnetic moment, and \( B \) is the magnetic field strength. 3. **Case 1: Magnets in Same Position**: - When the magnets are placed in the same position, the total magnetic moment \( M_{\text{total}} \) is: \[ M_{\text{total}} = M + 2M = 3M \] - Thus, the time period can be expressed as: \[ T_1 = 2\pi \sqrt{\frac{I_1 + I_2}{3M \cdot B}} \] - Given \( T_1 = 3 \) seconds, we can set up the equation: \[ 3 = 2\pi \sqrt{\frac{I_1 + I_2}{3M \cdot B}} \quad \text{(Equation 1)} \] 4. **Case 2: Magnets in Different Positions**: - When the magnets are placed in different positions, the total magnetic moment \( M_{\text{total}} \) becomes: \[ M_{\text{total}} = 2M - M = M \] - The time period for this case can be expressed as: \[ T_2 = 2\pi \sqrt{\frac{I_1 + I_2}{M \cdot B}} \quad \text{(Equation 2)} \] 5. **Finding the Relationship Between Time Periods**: - We can divide Equation 2 by Equation 1 to find the relationship between \( T_2 \) and \( T_1 \): \[ \frac{T_2}{T_1} = \frac{2\pi \sqrt{\frac{I_1 + I_2}{M \cdot B}}}{2\pi \sqrt{\frac{I_1 + I_2}{3M \cdot B}}} \] - Simplifying this gives: \[ \frac{T_2}{3} = \sqrt{\frac{3M}{M}} = \sqrt{3} \] - Therefore: \[ T_2 = 3\sqrt{3} \] 6. **Final Answer**: - The time period when the magnets are placed in different positions is: \[ T_2 = 3\sqrt{3} \text{ seconds} \]
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