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A rectangular coil of length 0.12 m and...

A rectangular coil of length `0.12 m` and width `0.1 m` having 50 turns of wire is suspended vertically in uniform magnetic field of strength 0.2 `Weber//m^(2)`. The coil carries a current of 2 A. If the plane of the coil is inclined at an angle,e of `30^(@)` with the direction of the field the torque required to keep the coil in stable equilibrium will be

A

`0.12Nm`

B

`0.15Nm`

C

`0.20Nm`

D

`0.24Nm`

Text Solution

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The correct Answer is:
To find the torque required to keep the rectangular coil in stable equilibrium, we can follow these steps: ### Step 1: Identify the parameters - Length of the coil (l) = 0.12 m - Width of the coil (w) = 0.1 m - Number of turns (N) = 50 - Current (I) = 2 A - Magnetic field strength (B) = 0.2 Weber/m² - Angle (θ) = 30° ### Step 2: Calculate the area of the coil The area (A) of the rectangular coil can be calculated using the formula: \[ A = l \times w \] Substituting the values: \[ A = 0.12 \, \text{m} \times 0.1 \, \text{m} = 0.012 \, \text{m}^2 \] ### Step 3: Determine the angle with respect to the magnetic field Since the coil is inclined at an angle of 30° with the magnetic field, the angle (φ) between the magnetic moment and the magnetic field is: \[ φ = 90° - θ = 90° - 30° = 60° \] ### Step 4: Calculate the magnetic moment (m) The magnetic moment (m) of the coil is given by: \[ m = N \times I \times A \] Substituting the values: \[ m = 50 \times 2 \, \text{A} \times 0.012 \, \text{m}^2 = 1.2 \, \text{A m}^2 \] ### Step 5: Calculate the torque (τ) The torque (τ) acting on the coil in a magnetic field is given by: \[ τ = m \times B \times \sin(φ) \] Substituting the values: \[ τ = 1.2 \, \text{A m}^2 \times 0.2 \, \text{Wb/m}^2 \times \sin(60°) \] Using the value of \(\sin(60°) = \frac{\sqrt{3}}{2}\): \[ τ = 1.2 \times 0.2 \times \frac{\sqrt{3}}{2} \] \[ τ = 0.24 \times \frac{\sqrt{3}}{2} \] \[ τ = 0.12 \sqrt{3} \, \text{N m} \] ### Step 6: Calculate the numerical value Using \(\sqrt{3} \approx 1.732\): \[ τ \approx 0.12 \times 1.732 \approx 0.20784 \, \text{N m} \] ### Final Answer The torque required to keep the coil in stable equilibrium is approximately: \[ τ \approx 0.21 \, \text{N m} \]
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