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The peak value of Alternating current is...

The peak value of Alternating current is `6`amp, then r.m.s. value of current will be

A

0.125

B

`3sqrt(3) A`

C

`3sqrt(2) A`

D

`2sqrt(3)`A

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The correct Answer is:
To find the root mean square (RMS) value of an alternating current (AC) given its peak value, we can use the relationship between the peak current (I₀) and the RMS current (I_rms). The formula is: \[ I_{rms} = \frac{I_0}{\sqrt{2}} \] ### Step-by-Step Solution: 1. **Identify the Peak Value**: The peak value of the alternating current is given as \( I_0 = 6 \, \text{A} \). 2. **Apply the RMS Formula**: Use the formula for RMS current: \[ I_{rms} = \frac{I_0}{\sqrt{2}} \] 3. **Substitute the Peak Value**: Substitute \( I_0 \) into the formula: \[ I_{rms} = \frac{6}{\sqrt{2}} \] 4. **Calculate the RMS Value**: To simplify \( \frac{6}{\sqrt{2}} \), multiply the numerator and denominator by \( \sqrt{2} \): \[ I_{rms} = \frac{6 \sqrt{2}}{2} = 3\sqrt{2} \, \text{A} \] 5. **Final Answer**: Therefore, the RMS value of the current is: \[ I_{rms} = 3\sqrt{2} \, \text{A} \approx 4.24 \, \text{A} \]
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