The coefficient of mutual inductance when magnetic flux change by `2xx10^(-2)Wb` and current changes by `0.01A`, will be

Options

A. 2H
B. 3H
C. 4H
D. 8H

Answer

To find the coefficient of mutual inductance (M) when the magnetic flux changes by \(2 \times 10^{-2} \, \text{Wb}\) and the current changes by \(0.01 \, \text{A}\), we can use the formula:

\[ M = \frac{d\Phi}{dI} \]

where:
- \(d\Phi\) is the change in magnetic flux,
- \(dI\) is the change in current.

### Step-by-Step Solution:

1. **Identify the given values**:
- Change in magnetic flux, \(d\Phi = 2 \times 10^{-2} \, \text{Wb}\)
- Change in current, \(dI = 0.01 \, \text{A}\)

2. **Convert the change in current to a more manageable form**:
- \(0.01 \, \text{A} = 10^{-2} \, \text{A}\)

3. **Substitute the values into the formula for mutual inductance**:
\[ M = \frac{d\Phi}{dI} = \frac{2 \times 10^{-2} \, \text{Wb}}{0.01 \, \text{A}} \]

4. **Perform the calculation**:
\[ M = \frac{2 \times 10^{-2}}{10^{-2}} = 2 \, \text{H} \]

5. **Conclusion**:
- The coefficient of mutual inductance \(M\) is \(2 \, \text{H}\) (Henry).

### Final Answer:
The coefficient of mutual inductance is \(2 \, \text{H}\).

---