A current of 5A is flowing at 220V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200V and 50% of power is lost, then the current in the secondary coil will be –

Options

A. `2.5A`
B. `5A`
C. `0.25 A`
D. `0.5 A`

Answer

To solve the problem step by step, we will use the information given about the transformer and the power loss.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Primary current (\(I_p\)) = 5 A
- Primary voltage (\(V_p\)) = 220 V
- Secondary voltage (\(V_s\)) = 2200 V
- Power loss = 50%

2. **Calculate Input Power:**
The input power (\(P_{in}\)) can be calculated using the formula:
\[ P_{in} = V_p \times I_p \]
Substituting the values:
\[ P_{in} = 220 \, \text{V} \times 5 \, \text{A} = 1100 \, \text{W} \]

3. **Calculate Output Power Considering Loss:**
Since 50% of the power is lost, the output power (\(P_{out}\)) is:
\[ P_{out} = P_{in} \times (1 - \text{loss fraction}) = P_{in} \times (1 - 0.5) = P_{in} \times 0.5 \]
Thus,
\[ P_{out} = 1100 \, \text{W} \times 0.5 = 550 \, \text{W} \]

4. **Relate Output Power to Secondary Current:**
The output power can also be expressed in terms of secondary voltage and current:
\[ P_{out} = V_s \times I_s \]
Rearranging for \(I_s\):
\[ I_s = \frac{P_{out}}{V_s} \]

5. **Substituting the Values:**
Now, substituting the known values:
\[ I_s = \frac{550 \, \text{W}}{2200 \, \text{V}} = 0.25 \, \text{A} \]

6. **Final Answer:**
Therefore, the current in the secondary coil (\(I_s\)) is:
\[ I_s = 0.25 \, \text{A} \]

### Summary:
The current in the secondary coil of the transformer is **0.25 A**.