A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If a voltage of 200V is applied across the primary coil , then the voltage in the secondary coil is :

Options

A. 100 V
B. 150 V
C. 200 V
D. 250 V

Answer

To solve the problem step by step, we will use the transformer equation that relates the primary and secondary voltages to the number of turns in the coils.

### Step-by-Step Solution:

1. **Identify the given values:**
- Number of turns in the primary coil (Np) = 1500 turns
- Number of turns in the secondary coil (Ns) = 1125 turns
- Voltage applied across the primary coil (Vp) = 200 V

2. **Write the transformer voltage equation:**
The relationship between the primary voltage (Vp), secondary voltage (Vs), number of turns in the primary (Np), and number of turns in the secondary (Ns) is given by the formula:
\[ \frac{Vs}{Vp} = \frac{Ns}{Np} \]

3. **Rearrange the equation to find Vs:**
To find the secondary voltage (Vs), we can rearrange the equation:
\[ Vs = Vp \times \frac{Ns}{Np} \]

4. **Substitute the known values into the equation:**
Now, substitute the values we have into the equation:
\[ Vs = 200 \, V \times \frac{1125}{1500} \]

5. **Calculate the fraction:**
First, calculate the fraction \(\frac{1125}{1500}\):
\[ \frac{1125}{1500} = 0.75 \]

6. **Calculate Vs:**
Now, substitute this value back into the equation for Vs:
\[ Vs = 200 \, V \times 0.75 = 150 \, V \]

7. **Conclusion:**
Therefore, the voltage in the secondary coil (Vs) is:
\[ Vs = 150 \, V \]

### Final Answer:
The voltage in the secondary coil is **150 V**.

---