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The angle of a prism is 30^(@). The rays...

The angle of a prism is `30^(@)`. The rays incident at `60^(@)` on one refracting face suffer a deviation of `30^(@)`. Then the angle of emergence is :

A

`0^(@)`

B

`30^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the angle of emergence (E) of a ray passing through a prism. The given data includes: - Angle of the prism (A) = 30° - Angle of incidence (i) = 60° - Angle of deviation (D) = 30° We can use the formula that relates these angles in a prism: \[ A + D = i + E \] ### Step-by-Step Solution: 1. **Write down the known values:** - Angle of prism (A) = 30° - Angle of incidence (i) = 60° - Angle of deviation (D) = 30° 2. **Substitute the known values into the formula:** \[ A + D = i + E \] Substituting the values: \[ 30° + 30° = 60° + E \] 3. **Simplify the equation:** \[ 60° = 60° + E \] 4. **Isolate E:** To find E, subtract 60° from both sides: \[ E = 60° - 60° \] \[ E = 0° \] 5. **Conclusion:** The angle of emergence (E) is 0°. ### Final Answer: The angle of emergence is \( 0° \).
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