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The relationship between phase differenc...

The relationship between phase difference `Deltaphi` and the path difference `Deltar` between two interfering waves is given by: (`lambda` = wavelength)

A

`Deltax = (lambda/(2pi))Deltaphi`

B

`Deltar = (2pi)/lambda Deltaphi`

C

`Deltaphi = (lambda/(2pi))Deltax`

D

`Deltaphi = 2(2pi)Deltax`

Text Solution

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The correct Answer is:
To derive the relationship between phase difference (ΔΦ) and path difference (Δr) for two interfering waves, we can follow these steps: ### Step 1: Understand the Definitions - **Path Difference (Δr)**: This is the difference in distance traveled by two waves arriving at a point. - **Phase Difference (ΔΦ)**: This is the difference in phase of the two waves when they arrive at that point. ### Step 2: Use the Relationship between Path Difference and Wavelength The path difference (Δr) is related to the wavelength (λ) of the waves. The relationship is given by: \[ \Delta r = n \lambda \] where \( n \) is an integer representing the number of wavelengths. ### Step 3: Relate Phase Difference to Path Difference The phase difference (ΔΦ) can be expressed in terms of the path difference. The relationship is given by: \[ \Delta \Phi = \frac{2\pi}{\lambda} \Delta r \] This equation states that the phase difference is proportional to the path difference, scaled by the factor \( \frac{2\pi}{\lambda} \). ### Step 4: Rearranging the Equation To express ΔΦ in terms of Δr, we can rearrange the equation: \[ \Delta \Phi = \frac{2\pi}{\lambda} \Delta r \] ### Conclusion Thus, the relationship between phase difference (ΔΦ) and path difference (Δr) is given by: \[ \Delta \Phi = \frac{2\pi}{\lambda} \Delta r \]
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