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A beam of menochromatic blue light of wa...

A beam of menochromatic blue light of wavelength 4200 Ål in air travels in water of refractive index 4/3. its wavelength in water will be

A

`4200 Å`

B

`5800 Å`

C

`4150 Å`

D

`3150 Å`

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The correct Answer is:
To find the wavelength of monochromatic blue light in water, we can use the relationship between the wavelength of light in different media and the refractive index. ### Step-by-Step Solution: 1. **Identify Given Values:** - Wavelength of light in air (\( \lambda_1 \)): 4200 Å (angstroms) - Refractive index of water (\( \mu_2 \)): \( \frac{4}{3} \) - Refractive index of air (\( \mu_1 \)): 1 (approximately) 2. **Use the Relationship Between Wavelength and Refractive Index:** The relationship between the wavelength in air and the wavelength in a medium is given by: \[ \frac{\lambda_1}{\lambda_2} = \frac{\mu_2}{\mu_1} \] Rearranging this gives: \[ \lambda_2 = \lambda_1 \times \frac{\mu_1}{\mu_2} \] 3. **Substitute the Known Values:** Substitute \( \lambda_1 = 4200 \) Å, \( \mu_1 = 1 \), and \( \mu_2 = \frac{4}{3} \): \[ \lambda_2 = 4200 \times \frac{1}{\frac{4}{3}} = 4200 \times \frac{3}{4} \] 4. **Calculate \( \lambda_2 \):** \[ \lambda_2 = 4200 \times \frac{3}{4} = 4200 \times 0.75 = 3150 \text{ Å} \] 5. **Conclusion:** The wavelength of the monochromatic blue light in water is \( \lambda_2 = 3150 \) Å. ### Final Answer: The wavelength of the blue light in water is **3150 Å**. ---
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