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The maximum intensities produced by two ...

The maximum intensities produced by two coherent waves of intensity `I_(1)` and `I_(2)` will be:

A

`I_(1) + I_(2)`

B

`I_(1)^(2) + I_(2)^(2)`

C

`I_(1) + I_(2) + 2sqrt(I_(1)I_(2))`

D

zero

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The correct Answer is:
To find the maximum intensity produced by two coherent waves of intensity \( I_1 \) and \( I_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Intensity Formula**: The net intensity \( I_{\text{net}} \) at any point due to two coherent waves can be expressed as: \[ I_{\text{net}} = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi \] where \( \phi \) is the phase difference between the two waves. 2. **Maximizing the Intensity**: To find the maximum intensity, we need to maximize the term \( \cos \phi \). The maximum value of \( \cos \phi \) is \( +1 \). 3. **Substituting the Maximum Value**: Substitute \( \cos \phi = 1 \) into the intensity formula: \[ I_{\text{max}} = I_1 + I_2 + 2\sqrt{I_1 I_2} \cdot 1 \] 4. **Simplifying the Expression**: This simplifies to: \[ I_{\text{max}} = I_1 + I_2 + 2\sqrt{I_1 I_2} \] 5. **Conclusion**: Therefore, the maximum intensity produced by the two coherent waves is: \[ I_{\text{max}} = I_1 + I_2 + 2\sqrt{I_1 I_2} \] ### Final Answer: The maximum intensity produced by two coherent waves of intensity \( I_1 \) and \( I_2 \) is: \[ I_{\text{max}} = I_1 + I_2 + 2\sqrt{I_1 I_2} \]
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VMC MODULES ENGLISH-RAY OPTICS AND WAVE OPTICS -ENABLE
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