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Two beams of light are incident normally...

Two beams of light are incident normally on water (R.l. = `4/3`). If the beam 1 passes through a glass (R.l. = `3/2`) slab of height h as shown in the figure, the time difference for both beams for reaching the bottom is

A

zero

B

`(h^('))/(6C)`

C

`(6h)/C`

D

`h/(6C)`

Text Solution

Verified by Experts

The correct Answer is:
D
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