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If two sources have a randomly varying p...

If two sources have a randomly varying phase difference f(t), the resultant intensity will be given by:

A

`2I_(0)`

B

`I_(0)//2`

C

`2I_(0)`

D

`I_(0)//sqrt(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to understand the concept of intensity from two incoherent sources with a randomly varying phase difference. ### Step-by-Step Solution: 1. **Understanding Incoherent Sources**: - Incoherent sources are those that do not have a fixed phase relationship. This means that the phase difference between the two sources can change randomly over time. **Hint**: Remember that incoherent sources do not interfere constructively or destructively in a predictable manner. 2. **Intensity of Individual Sources**: - Let the intensity of each source be \( I_0 \). **Hint**: The intensity of a wave is proportional to the square of its amplitude, but here we are given the intensity directly. 3. **Resultant Intensity of Incoherent Sources**: - For incoherent sources, the resultant intensity is simply the sum of the individual intensities. Therefore, if we have two sources with intensities \( I_1 \) and \( I_2 \), the resultant intensity \( I \) is given by: \[ I = I_1 + I_2 \] **Hint**: This is a key property of incoherent sources; they add up linearly. 4. **Calculating Resultant Intensity**: - Since both sources have the same intensity \( I_0 \), we can substitute: \[ I = I_0 + I_0 = 2I_0 \] **Hint**: Make sure to substitute the values correctly. 5. **Conclusion**: - The resultant intensity of the two incoherent sources with randomly varying phase difference is \( 2I_0 \). **Hint**: Always check if the sources are coherent or incoherent before applying formulas related to intensity. ### Final Answer: The resultant intensity will be \( 2I_0 \).
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