Which is not correctly matched ?

Options

A. `XeO_3` : Trigonal bipyramidal
B. `CIF_3` : T-shape
C. `XeF_4`: Square planar
D. `XeF_2`: Linear shape

Answer

To determine which option is not correctly matched in terms of molecular geometry and hybridization, we can analyze each compound mentioned in the question.

### Step-by-Step Solution:

1. **Analyze XeO3:**
- **Valence Electrons:** Xenon (Xe) has 8 valence electrons, and each oxygen (O) has 6. For XeO3, we have 1 Xe and 3 O, giving us a total of 8 + (3 × 6) = 26 valence electrons.
- **Bonding:** Xe forms 3 sigma bonds with the 3 O atoms. This leaves 1 lone pair on Xe.
- **Steric Number:** The steric number is calculated as the number of sigma bonds plus the number of lone pairs. Here, it is 3 (sigma bonds) + 1 (lone pair) = 4.
- **Hybridization:** With a steric number of 4, the hybridization is sp³.
- **Shape:** The shape corresponding to sp³ hybridization with one lone pair is trigonal pyramidal, not trigonal bipyramidal.
- **Conclusion:** The match for XeO3 is incorrect as it is stated to be trigonal bipyramidal.

2. **Analyze ClF3:**
- **Valence Electrons:** Chlorine (Cl) has 7 valence electrons, and each fluorine (F) has 7. For ClF3, we have 1 Cl and 3 F, giving us a total of 7 + (3 × 7) = 28 valence electrons.
- **Bonding:** Cl forms 3 sigma bonds with the 3 F atoms and has 2 lone pairs.
- **Steric Number:** The steric number is 3 (sigma bonds) + 2 (lone pairs) = 5.
- **Hybridization:** With a steric number of 5, the hybridization is sp³d.
- **Shape:** The shape corresponding to sp³d hybridization with two lone pairs is T-shaped.
- **Conclusion:** The match for ClF3 is correct.

3. **Analyze XeF4:**
- **Valence Electrons:** Xenon (Xe) has 8 valence electrons, and each fluorine (F) has 7. For XeF4, we have 1 Xe and 4 F, giving us a total of 8 + (4 × 7) = 36 valence electrons.
- **Bonding:** Xe forms 4 sigma bonds with the 4 F atoms and has 2 lone pairs.
- **Steric Number:** The steric number is 4 (sigma bonds) + 2 (lone pairs) = 6.
- **Hybridization:** With a steric number of 6, the hybridization is sp³d².
- **Shape:** The shape corresponding to sp³d² hybridization with 2 lone pairs is square planar.
- **Conclusion:** The match for XeF4 is correct.

4. **Analyze XeF2:**
- **Valence Electrons:** Xenon (Xe) has 8 valence electrons, and each fluorine (F) has 7. For XeF2, we have 1 Xe and 2 F, giving us a total of 8 + (2 × 7) = 22 valence electrons.
- **Bonding:** Xe forms 2 sigma bonds with the 2 F atoms and has 3 lone pairs.
- **Steric Number:** The steric number is 2 (sigma bonds) + 3 (lone pairs) = 5.
- **Hybridization:** With a steric number of 5, the hybridization is sp³d.
- **Shape:** The shape corresponding to sp³d hybridization with 3 lone pairs is linear.
- **Conclusion:** The match for XeF2 is correct.

### Final Conclusion:
The only incorrect match is for **XeO3**, which is stated to be trigonal bipyramidal but is actually trigonal pyramidal.