The atomic numbers of three elements L,M and P are `Z,Z+1 and Z+2` respectively. If P belong to alkali metal group, then the bond present in the compound obtained by the combination of the L and P is :

Options

A. Electrovalent
B. Covalent
C. Coordinate
D. Not known

Answer

To solve the problem, we need to analyze the information given about the elements L, M, and P based on their atomic numbers and their group classifications in the periodic table.

### Step-by-Step Solution:

1. **Identify the Atomic Numbers**:
- Let the atomic number of element L be \( Z \).
- Therefore, the atomic number of element M will be \( Z + 1 \).
- The atomic number of element P will be \( Z + 2 \).

2. **Determine the Group of Element P**:
- The problem states that element P belongs to the alkali metal group. Alkali metals are found in Group 1 of the periodic table.

3. **Identify the Groups of Elements L and M**:
- Since P (with atomic number \( Z + 2 \)) is in Group 1, we can deduce that:
- The element with atomic number \( Z + 1 \) (which is M) must be in Group 18 (the noble gases).
- The element with atomic number \( Z \) (which is L) must be in Group 17 (the halogens).

4. **Characterize the Elements**:
- Alkali metals (like P) are electropositive and tend to lose one electron to form cations.
- Halogens (like L) are electronegative and tend to gain one electron to form anions.

5. **Determine the Type of Bond**:
- When an alkali metal (P) reacts with a halogen (L), the electropositive nature of P and the electronegative nature of L lead to the formation of an ionic bond (also known as an electrovalent bond).
- This is because the alkali metal donates an electron to the halogen, resulting in the formation of oppositely charged ions that attract each other.

6. **Conclusion**:
- Therefore, the bond present in the compound formed by the combination of elements L and P is an ionic bond.

### Final Answer:
The bond present in the compound obtained by the combination of L and P is an **ionic bond**.

---