A molecule is formed by `sp^3d^2` hybridisation. Bond angle in it is :

Options

A. `90^@`
B. `109^@28`
C. `90^@ and 120^@`
D. `120^@`.

Answer

To determine the bond angles in a molecule formed by `sp^3d^2` hybridization, we can follow these steps:

### Step 1: Identify the Hybridization
The hybridization `sp^3d^2` indicates that there are 6 hybrid orbitals formed from one s orbital, three p orbitals, and two d orbitals.

### Step 2: Determine the Steric Number
The steric number is calculated as the number of atoms bonded to the central atom plus the number of lone pairs on the central atom. For `sp^3d^2` hybridization, the steric number is 6, which typically corresponds to an octahedral geometry.

### Step 3: Understand the Geometry
In an octahedral geometry, the arrangement of the atoms around the central atom is such that there are 6 positions where the atoms can be placed. This arrangement leads to specific bond angles.

### Step 4: Identify Bond Angles
In a perfect octahedral structure, the bond angles between the atoms are:
- 90 degrees between adjacent atoms in the same plane.
- 180 degrees between atoms that are directly opposite each other.

### Step 5: Conclusion
Thus, the bond angles in a molecule with `sp^3d^2` hybridization are primarily 90 degrees and 180 degrees.

### Final Answer
The bond angle in a molecule formed by `sp^3d^2` hybridization is **90 degrees**.

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