The number and type of bonds between two atoms in `C_3O_2` molecules are

Options

A. three sigma `(sigma)` and two `(pi)` bonds
B. four `(sigma)` and four `(pi)` bonds
C. tow sigma and one and a half `(pi)` bonds
D. six sigma bonds

Answer

To determine the number and type of bonds between the atoms in the molecule C₃O₂ (carbon suboxide), we can follow these steps:

### Step 1: Identify the structure of C₃O₂
C₃O₂ is known as carbon suboxide. The molecular structure consists of three carbon atoms and two oxygen atoms. The arrangement can be visualized as follows:
- The central carbon atom is bonded to two terminal carbon atoms.
- Each terminal carbon atom is also double-bonded to an oxygen atom.

### Step 2: Draw the Lewis structure
To visualize the bonding, we can draw the Lewis structure of C₃O₂:
- Carbon atoms are connected in a chain: C=C=C.
- Each terminal carbon (C) is double-bonded to an oxygen (O) atom: C=O.

### Step 3: Count the types of bonds
Now, we need to identify the types of bonds:
- Between the carbon atoms, there are double bonds. Each double bond consists of one sigma (σ) bond and one pi (π) bond.
- Between each carbon and oxygen, there are also double bonds, which again consist of one sigma bond and one pi bond.

### Step 4: Total the bonds
- For the carbon-carbon (C=C) bonds, there are 2 double bonds:
- 2 sigma bonds (one for each double bond)
- 2 pi bonds (one for each double bond)

- For the carbon-oxygen (C=O) bonds, there are 2 double bonds:
- 2 sigma bonds (one for each double bond)
- 2 pi bonds (one for each double bond)

### Step 5: Summarize the total number of bonds
Now, we can summarize the total number of bonds:
- Total sigma bonds = 2 (C=C) + 2 (C=O) = 4 sigma bonds
- Total pi bonds = 2 (C=C) + 2 (C=O) = 4 pi bonds

### Conclusion
Thus, in the C₃O₂ molecule, there are a total of **4 sigma bonds** and **4 pi bonds**.

### Final Answer
The number and type of bonds between the two atoms in C₃O₂ are **4 sigma bonds and 4 pi bonds**.

---