Among the following which one is a wrong statement-

Options

A. `PH_5 and BiCI_5` do not exist
B. `p pi - d pi ` bonds are present in `SO_2`.
C. `SeF_4 and CH_4` have different shape
D. `I_(3)^(-)` has bent geometry

Answer

To determine which statement is incorrect among the given options, let's analyze each statement step by step.

### Step 1: Analyzing the first statement about PH5
- **Statement**: PH5 does not exist because hydrogen is less electronegative and cannot exert charge contraction on phosphorus.
- **Analysis**: Phosphorus typically forms compounds with a maximum of 5 bonds due to its ability to expand its octet. However, PH5 is not stable due to the inability of hydrogen to stabilize the higher oxidation state of phosphorus. Therefore, this statement is correct.

### Step 2: Analyzing the second statement about BCl5
- **Statement**: BCl5 does not exist.
- **Analysis**: Boron can form BCl3, but BCl5 is not stable due to the inability of boron to accommodate more than 6 electrons in its valence shell. Thus, this statement is also correct.

### Step 3: Analyzing the third statement about SO2
- **Statement**: SO2 contains p pi and d pi bonds.
- **Analysis**: Sulfur (S) is in the third period and can utilize d orbitals for bonding. The presence of p pi and d pi bonds in SO2 is indeed possible. Therefore, this statement is correct.

### Step 4: Analyzing the fourth statement about SeF4 and CH4
- **Statement**: SeF4 and CH4 have different shapes.
- **Analysis**: Both SeF4 and CH4 have tetrahedral geometry. However, SeF4 is actually seesaw-shaped due to the presence of lone pairs on selenium, while CH4 is tetrahedral. Therefore, this statement is incorrect.

### Step 5: Analyzing the fifth statement about I3-
- **Statement**: I3- has bent geometry.
- **Analysis**: The I3- ion has a linear geometry due to the three iodine atoms, with the central iodine atom bonded to two terminal iodine atoms. Thus, this statement is also incorrect.

### Conclusion
After analyzing all the statements, the incorrect statement is:
- **SeF4 and CH4 have different shapes.** (This statement is misleading as they do not have the same geometry.)

### Final Answer
The wrong statement among the options is: **SeF4 and CH4 have different shapes.**

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