If pressure becomes double at the same absolute temperature on `2L CO_(2)`, then the volume of `CO_(2)` becomes

Options

A. 2L
B. 4L
C. 5L
D. 1L

Answer

To solve the problem, we will use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas are held constant.

### Step-by-Step Solution:

1. **Identify Initial Conditions**:
- Initial volume \( V_1 = 2 \, \text{L} \)
- Initial pressure \( P_1 = P \) (Let’s denote the initial pressure as \( P \))

2. **Determine Final Conditions**:
- Final pressure \( P_2 = 2P \) (The pressure doubles)

3. **Apply Boyle's Law**:
- According to Boyle's Law, we have the relationship:
\[ P_1 V_1 = P_2 V_2 \]
- Substitute the known values into the equation:
\[ P \cdot 2 \, \text{L} = 2P \cdot V_2 \]

4. **Simplify the Equation**:
- Cancel \( P \) from both sides (assuming \( P \neq 0 \)):
\[ 2 \, \text{L} = 2 \cdot V_2 \]

5. **Solve for \( V_2 \)**:
- Divide both sides by 2:
\[ V_2 = 1 \, \text{L} \]

### Conclusion:
The final volume \( V_2 \) of the \( CO_2 \) gas when the pressure doubles at constant temperature is \( 1 \, \text{L} \).

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