40 ml of gaseous mixture of CO and ethyne is mixed with 100 ml of `O_2` and burnt. The volume of gases after combustion is 105 ml. The composition of the original mixture is

Options

A. 25 ml CO, 15 ml ethyne
B. 15 ml CO, 25 ml ethyne
C. 10 ml CO, 30 ml ethyne
D. 20 ml CO, 20 ml ethyne

Answer

To solve the problem step by step, we will determine the composition of the original gaseous mixture of carbon monoxide (CO) and ethyne (C2H2) that was mixed with oxygen (O2) and burnt.

### Step 1: Define Variables
Let:
- \( x \) = volume of carbon monoxide (CO) in ml
- \( 40 - x \) = volume of ethyne (C2H2) in ml (since the total volume of the mixture is 40 ml)