Home
Class 12
CHEMISTRY
8.4 " mL of " gaseous hydrocarbon A was ...

8.4 " mL of " gaseous hydrocarbon A was burnt with 50 " mL of " `O_2` in a eudiometer tube. The volume of the products after cooling to room temperature was 37.4 mL. When reacted with NaOH, the volume contracted to 3.8 mL. What is the molecular formula of A.

A

`C_4H_6`

B

`C_2H_2`

C

`C_2H_8`

D

`C_5H_10`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    VMC MODULES ENGLISH|Exercise IMPECCABLE|50 Videos

  • STATES OF MATTER

    VMC MODULES ENGLISH|Exercise ENABLE|50 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - H|8 Videos

  • STATES OF MATTER

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-I|10 Videos

Similar Questions

Explore conceptually related problems

20 " mL of " a gasous bydrocarbon (A) was exploded with excess of O_2 in an eudiometer tube. On cooling, the volume was reduced by 50 mL. On further treatment with KOH, there was further contraction of 40 mL. The molecular formula of the hydrocarbon A is (a). C_2H_6 (b). C_2H_4 C_3H_6 (d). C_3H_8

Twenty millilitres of a gaseous hydrocarbon (A) was exploded with excess of oxygen in eudiometer tube. On cooling, the volume was reduced by 50ml. On further treatement with KOH solution, there was a further contraction of 40 ml. The molecular formula of the hydrocarbon (A) is:

Ten millilitre of a gaseous hydrocarbon was burnt completely in 80 ml of O_2 at STP. The volume of the remaining gas is 70 ml. The volume became 50 ml, on treatment with NaOH . The formula of the hydrocarbon is:

Sixteen millilitre of a hydrocarbon gas was exploded with an excess of O_2 . On cooling ,t he volume of the resulting gaseous mixture was reduced by 48 ml. When KOH was added, there was a further decrease of 48 ml in volume. Find the molecular formula of the compound.

16 " mL of " a gaseous compound C_(n)H_(3n)O_(m) was mixed with 60 " mL of " O_2 and sparked. The gas mixture on cooling occupied 44 mL. After treatment with NaOH solution, the volume of gas remaining was 12 mL. Deduce the formula of the compound.

Twenty millilitres of a gaseous hydrocarbon (A) was exploded with excess of oxygen in eudiometer tube. On cooling, the volume was reduced by 50ml. On further treatement with KOH solution, there was a further contraction of 40 ml. Compound (D) is:

Twenty millilitres of a gaseous hydrocarbon (A) was exploded with excess of oxygen in eudiometer tube. On cooling, the volume was reduced by 50ml. On further treatement with KOH solution, there was a further contraction of 40 ml. Compound (E) is:

Twenty millilitres of a gaseous hydrocarbon (A) was exploded with excess of oxygen in eudiometer tube. On cooling, the volume was reduced by 50ml. On further treatement with KOH solution, there was a further contraction of 40 ml. Compound (G) is:

Twenty millilitres of a gaseous hydrocarbon (A) was exploded with excess of oxygen in eudiometer tube. On cooling, the volume was reduced by 50ml. On further treatement with KOH solution, there was a further contraction of 40 ml. Compound (C) is:

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

VMC MODULES ENGLISH-STATES OF MATTER-EFFICIENT
  1. Gaseous benzene reacts with hydrogen gas in the presence of nickel cat...

    Text Solution

    |

  2. A glass bulb is connected to an open-limb manometer. The level of merc...

    Text Solution

    |

  3. For two gases, A and B with molecular weights M(A) and M(B). It is obs...

    Text Solution

    |

  4. Certain volume of a gas exerts on its walls some pressure at a particu...

    Text Solution

    |

  5. If X(m), X(p) and X(v) represent mole fraction, pressure fraction an...

    Text Solution

    |

  6. The root mean square speed of the molecules of a diatomic gas is v. Wh...

    Text Solution

    |

  7. At 27^(@) C, hydrogen is leaked through a tiny hole into a vessel for ...

    Text Solution

    |

  8. 10 " mL of " a gaseous organic compound containing C, H and O only was...

    Text Solution

    |

  9. Five millilitires of a gas (A) containing only C and H was mixed with ...

    Text Solution

    |

  10. One mole of nitrogen gas at 0.8 atm takes 38 s to diffuse through a pi...

    Text Solution

    |

  11. The average velocity of gas molecules is 400 m/sec calculate its rms v...

    Text Solution

    |

  12. A graph is plotted between PV(m) along Y-axis and P along X-axis, wher...

    Text Solution

    |

  13. 1.0 litre of N(2) and 7/8 litre of O(2) at the same temperature and pr...

    Text Solution

    |

  14. The volumes of two vessels at same temperature are in the ratio of 2 :...

    Text Solution

    |

  15. An evacuated glass vessel weighs 50 gm when empty, 148.0 gm filled wit...

    Text Solution

    |

  16. A spherical ballon of 21 cm diameter is to be filled with H(2) at NTP ...

    Text Solution

    |

  17. At 30^(@)C and 720 mm of Hg, the density of a gas is 1.5 g// l t. Calc...

    Text Solution

    |

  18. Density of dry air containing only N2 and O2 is 1.15 g/L at 740 mm of...

    Text Solution

    |

  19. A gas bulb of 1 L capacity contains 2.0xx10^(11) molecules of nitrogen...

    Text Solution

    |

  20. 8.4 " mL of " gaseous hydrocarbon A was burnt with 50 " mL of " O2 in ...

    Text Solution

    |