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In the temperature changes from 27^(@)C ...

In the temperature changes from `27^(@)C` to `127^(@)C`, the relative percentage change in RMS velocity is

A

1.56

B

2.56

C

15.6

D

82.4

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The correct Answer is:
To solve the problem of finding the relative percentage change in the RMS (Root Mean Square) velocity when the temperature changes from 27°C to 127°C, we can follow these steps: ### Step-by-Step Solution: 1. **Convert Temperatures to Kelvin**: - The formula to convert Celsius to Kelvin is: \[ T(K) = T(°C) + 273 \] - For 27°C: \[ T_1 = 27 + 273 = 300 \, K \] - For 127°C: \[ T_2 = 127 + 273 = 400 \, K \] 2. **Understand the Formula for RMS Velocity**: - The RMS velocity (\(v_{rms}\)) is given by: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] - Here, \(R\) is the universal gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass of the gas. 3. **Calculate the RMS Velocities**: - For \(T_1\) (300 K): \[ v_{rms1} = \sqrt{\frac{3R \cdot 300}{M}} \] - For \(T_2\) (400 K): \[ v_{rms2} = \sqrt{\frac{3R \cdot 400}{M}} \] 4. **Find the Ratio of RMS Velocities**: - The ratio of the two RMS velocities can be expressed as: \[ \frac{v_{rms2}}{v_{rms1}} = \frac{\sqrt{400}}{\sqrt{300}} = \sqrt{\frac{400}{300}} = \sqrt{\frac{4}{3}} \approx 1.1547 \] 5. **Calculate the Change in RMS Velocity**: - The change in RMS velocity can be expressed as: \[ \frac{v_{rms2} - v_{rms1}}{v_{rms1}} = \frac{v_{rms2}/v_{rms1} - 1}{1} \] - Substituting the ratio: \[ \frac{v_{rms2} - v_{rms1}}{v_{rms1}} = 1.1547 - 1 = 0.1547 \] 6. **Calculate the Percentage Change**: - The percentage change in RMS velocity is: \[ \text{Percentage Change} = \left(0.1547\right) \times 100 \approx 15.47\% \] ### Final Answer: The relative percentage change in RMS velocity when the temperature changes from 27°C to 127°C is approximately **15.4%**.
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