Home
Class 12
CHEMISTRY
The internal energy change when a system...

The internal energy change when a system goes fromk state `A` to `B` is `40 kJ mol^(-1)`. If the system goes from `A` to `B` by a reversible path and returns to state `A` by an irreversible path, what would be the net change in internal energy?

A

`lt 40 kJ`

B

Zero

C

`40 kJ`

D

`gt 40kJ`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the change in internal energy as the system transitions between states A and B, and then back to A. ### Step-by-Step Solution: 1. **Identify the Change in Internal Energy from A to B**: - The problem states that the internal energy change when the system goes from state A to state B is given as \( \Delta U_{A \to B} = 40 \, \text{kJ mol}^{-1} \). 2. **Understand the Nature of Internal Energy**: - Internal energy (U) is a state function. This means that the change in internal energy depends only on the initial and final states of the system, not on the path taken to get there. 3. **Consider the Return Path from B to A**: - The system returns from state B back to state A. The path taken for this return is irreversible. However, since internal energy is a state function, the change in internal energy for this part of the process is also determined solely by the initial and final states. 4. **Calculate the Change in Internal Energy for the Entire Process**: - For a complete cycle (from A to B and then back to A), the overall change in internal energy can be expressed as: \[ \Delta U_{\text{total}} = \Delta U_{A \to B} + \Delta U_{B \to A} \] - Since the system returns to its initial state A, we have: \[ \Delta U_{B \to A} = -\Delta U_{A \to B} = -40 \, \text{kJ mol}^{-1} \] - Therefore, the total change in internal energy is: \[ \Delta U_{\text{total}} = 40 \, \text{kJ mol}^{-1} + (-40 \, \text{kJ mol}^{-1}) = 0 \, \text{kJ mol}^{-1} \] 5. **Conclusion**: - The net change in internal energy when the system returns to state A after going from A to B and back to A is \( 0 \, \text{kJ mol}^{-1} \). ### Final Answer: The net change in internal energy is \( 0 \, \text{kJ mol}^{-1} \). ---
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Efficient|48 Videos
  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Impeccable|48 Videos
  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Impeccable|48 Videos
  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|44 Videos

Similar Questions

Explore conceptually related problems

A system changes from state X to Y with a change in internal energy measuring to "25 kJ mol"^(-1) , by a reversible path and returns from Y to X by an irreversible path. What will be the net change in internal energy?

A system changes from state X to Y with a change in internal energy measuring to "25 kJ mol"^(-1) , by a reversible path and returns from Y to X by an irreversible path. What will be the net change in internal energy?

160 J of work is done on the system and at the same time 100 J of heat is given out. What is the change in the internal energy ?

180 J of work is done on the system and at the same time 120 J of heat is given out. What is the change in the internal energy?

A mono-atomic gas is taken along path AB as shown. Calculate change in internal energy of the gas.

The internal energy U is a unique function of any state because change in U

Calculate DeltaU , internal energy change of a system, if it absorbs 25 kJ of heat and does 5kJ of work.

If 150 J of heat is added to a system and the work done by the system is 110 j. then change in internal energy wil be

A system absorbs 50 kJ heat and does 20 kJ of work. What is the net change in the internal energy of the system ?

How will you find the change in internal energy of a system when it melts ?

VMC MODULES ENGLISH-THERMODYNAMICS & THERMOCHEMISTRY-Enable
  1. For which one of the following equations DeltaH(r)^(@) equal to DeltaH...

    Text Solution

    |

  2. In an irreversible process taking place at constant T and P and in whi...

    Text Solution

    |

  3. The internal energy change when a system goes fromk state A to B is 40...

    Text Solution

    |

  4. If a 298K the bond energies of C-H,C-C,C=C and H-H bonds are respectiv...

    Text Solution

    |

  5. In a closed insulated container a liquid is stirred with a paddle to i...

    Text Solution

    |

  6. When 1 mole gas is heated at constant volume, temperature is raised fr...

    Text Solution

    |

  7. A gas occupies 2 litre at STP. It is provided 300 joule heat so that i...

    Text Solution

    |

  8. In order to decompose 9 grams of water 142.5 KJ heat is required. Henc...

    Text Solution

    |

  9. 2Zn + O(2) to 2Zn O Delta G^(@) = - 616 J 2Zn + S(2) to 2 Zn S ...

    Text Solution

    |

  10. Entropy change involve in conversation of 1mole of liquid water at 373...

    Text Solution

    |

  11. Heat of neutralization of strong acid against strong base is constant ...

    Text Solution

    |

  12. The free energy change for a reversible reaction at equilibrium is: ...

    Text Solution

    |

  13. When enthalpy and entropy change for a chemical reaction are -2.5 xx10...

    Text Solution

    |

  14. What is the free energy change, 'DeltaG' When 1.0 mole of water at 100...

    Text Solution

    |

  15. The combustion enthalpies of carbon, hydrogen and methane are -395.5 "...

    Text Solution

    |

  16. Identify the correct statement regarding entropy

    Text Solution

    |

  17. Equal volumes of methanoic acid and sodium hydroxide are mixed. If x i...

    Text Solution

    |

  18. The neutralization of a strong acid by a strong base liberates an amou...

    Text Solution

    |

  19. The equilibrium constant of a reaction at 298 K is 5 xx 10^(-3) and at...

    Text Solution

    |

  20. In an isochoric process the increase in internal energy is

    Text Solution

    |