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In the complete oombustion of butanol C4...

In the complete oombustion of butanol `C_4H_9OH (I)", if "triangleH` is enthalpy of combustion and AE is the heat of combustion at constant volume, then

A

`triangleH lt triangleE`

B

`triangleH=triangleE`

C

`triangleH gt triangleE`

D

`triangleH, triangle` relation cannot be predicted

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To find the relationship between the enthalpy of combustion (ΔH) and the heat of combustion at constant volume (ΔE) for the complete combustion of butanol (C₄H₉OH), we will follow these steps: ### Step 1: Write the balanced chemical equation for the combustion of butanol. The complete combustion of butanol can be represented as: \[ C_4H_9OH (l) + O_2 (g) \rightarrow 4 CO_2 (g) + 5 H_2O (l) \] ### Step 2: Identify the number of moles of gaseous products and reactants. In the balanced equation: - Products: 4 moles of CO₂ (g) and 5 moles of H₂O (l) - Reactants: 1 mole of C₄H₉OH (l) and x moles of O₂ (g) To find the moles of O₂ needed, we can balance the equation: \[ C_4H_9OH + 6 O_2 \rightarrow 4 CO_2 + 5 H_2O \] Thus, we have: - Total moles of products (gaseous): 4 (from CO₂) + 0 (from H₂O) = 4 - Total moles of reactants (gaseous): 6 (from O₂) ### Step 3: Calculate ΔN_G (change in the number of moles of gas). Using the formula: \[ \Delta N_G = \text{(moles of gaseous products)} - \text{(moles of gaseous reactants)} \] Substituting the values: \[ \Delta N_G = 4 - 6 = -2 \] ### Step 4: Use the relationship between ΔH and ΔE. The relationship between the enthalpy change (ΔH) and the internal energy change (ΔE) at constant volume is given by: \[ \Delta H = \Delta E + \Delta N_G RT \] Substituting ΔN_G: \[ \Delta H = \Delta E + (-2)RT \] This simplifies to: \[ \Delta H = \Delta E - 2RT \] ### Step 5: Analyze the relationship. From the equation: \[ \Delta H = \Delta E - 2RT \] We can deduce that: \[ \Delta E = \Delta H + 2RT \] This implies that ΔE is greater than ΔH because 2RT is a positive term. ### Conclusion: Thus, the relationship shows that the heat of combustion at constant volume (ΔE) is greater than the enthalpy of combustion (ΔH).
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