What can be accurately predicted for the isomerization reaction between gaseous penta-1,4-diene and gaseous penta-1.3-diene?

Options

A. The process is exothermic
B. Enthalpy change of the reaction is same as resonance energy of the product
C. Magnitude of enthalpy of combustion of product is more than that of the reactant
D. Combustion of the reactant will be exothermic while the same for the products will bc endothermic.

Answer

To solve the problem regarding the isomerization reaction between gaseous penta-1,4-diene and gaseous penta-1,3-diene, we can follow these steps:

### Step 1: Identify the Structures
- **Penta-1,4-diene**: This compound has a structure where the double bonds are located between carbon 1 and 2, and between carbon 4 and 5.
- **Penta-1,3-diene**: In this compound, the double bonds are located between carbon 1 and 2, and between carbon 3 and 4.

### Step 2: Determine the Type of Isomerism
- The two compounds are structural isomers, specifically positional isomers, because they have the same molecular formula (C5H8) but differ in the position of the double bonds.

### Step 3: Analyze the Isomerization Reaction
- Isomerization is the process where one isomer is transformed into another. In this case, penta-1,4-diene can convert to penta-1,3-diene and vice versa.

### Step 4: Assess the Thermodynamic Nature of the Reaction
- The isomerization process typically involves a change in energy. In this case, it is known that the isomerization of alkenes can be exothermic, meaning that energy is released during the reaction.

### Step 5: Conclusion
- Based on the analysis, we can accurately predict that the isomerization reaction between gaseous penta-1,4-diene and gaseous penta-1,3-diene is exothermic. Therefore, the correct option is that the reaction is exothermic.

### Final Answer
The isomerization reaction between gaseous penta-1,4-diene and gaseous penta-1,3-diene is exothermic.

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