The dissociation equilibrium of a gas AB, can be represented as The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant K,, and total pressure p is
(a)`(2K_(p)//p)`
(b)`(2K_(p)//p)^(1//3)`
(c)`(2K_(p)//p)^(1//2)`
(c)`(K_(p)//p)`

Options

A. `((2K_(p))/(P))`
B. `((2K_(p))/(P))^(1//3)`
C. `((2K_(p))/(P))^(1//2)`
D. `((K_(p))/(P))`

Answer

B