To have more sulphide ion concentraion `H_(2)S` should be passed through

Options

A. 1 N HCI solution
B. 0.1 M HCI solution
C. A neutral solution such as water
D. An ammonical solution

Answer

To solve the question of how to increase the concentration of sulfide ions (S²⁻) by passing hydrogen sulfide (H₂S) through a solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Dissociation of H₂S**:
H₂S can dissociate in water to produce hydrogen ions (H⁺) and sulfide ions (S²⁻):
\[ H_2S \rightleftharpoons H^+ + HS^- \]
\[ HS^- \rightleftharpoons H^+ + S^{2-} \]
Here, H₂S can produce both hydrogen ions and sulfide ions.

2. **Applying Le Chatelier's Principle**:
According to Le Chatelier's Principle, if we want to increase the concentration of sulfide ions, we can manipulate the equilibrium by changing the concentration of reactants or products.

3. **Increasing H⁺ Concentration**:
To shift the equilibrium to the right (towards the formation of more sulfide ions), we can increase the concentration of hydrogen ions (H⁺). This can be done by adding a strong acid such as hydrochloric acid (HCl) to the solution.

4. **Choosing the Right Concentration of HCl**:
We have two options for HCl concentration: 1 normal (1 N) HCl and 0.1 molar (0.1 M) HCl. Since normality (N) for HCl is equal to molarity (M) in this case, 1 N HCl has a higher concentration of H⁺ ions compared to 0.1 M HCl.

5. **Conclusion**:
Therefore, to increase the concentration of sulfide ions, we should pass H₂S through a solution of 1 N HCl. This will provide a higher concentration of H⁺ ions, shifting the equilibrium to the right and producing more sulfide ions.

### Final Answer:
To have more sulfide ion concentration, H₂S should be passed through a 1 N HCl solution.

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