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The pK(b) of CN^(Theta) is 4.7. The pH i...

The `pK_(b)` of `CN^(Theta)` is `4.7`. The `pH` is solution prepared by mixing `2.5 mol` of `2.5 mol` of `KCN` of `2.5 mol` of `HCN` in water and making the total volume upto `500mL` is

A

9.3

B

7.3

C

10.3

D

8.3

Text Solution

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The correct Answer is:
A
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VMC MODULES ENGLISH-ICONIC EQUILIBRIUM-EFFICIENT
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